Chapter 7: Geometry — Area, Perimeter & Volume

Pre-Algebra • Middle School • MathHub Global • Updated February 2026

Geometry brings algebra to life by connecting formulas to real shapes and spaces. In this chapter you will learn the vocabulary of basic geometry, classify angles and triangles, and master formulas for perimeter, area, surface area, and volume. We close with the Pythagorean theorem — one of the most celebrated results in all of mathematics.

7.1 Basic Geometry Vocabulary

Fundamental Terms

Types of Angles

Angle TypeMeasureSymbol / Description
Acute$0^\circ < \theta < 90^\circ$Sharp angle
Right$\theta = 90^\circ$Square corner; marked with a small square
Obtuse$90^\circ < \theta < 180^\circ$Wider than a right angle
Straight$\theta = 180^\circ$A line
Reflex$180^\circ < \theta < 360^\circ$Greater than a straight angle

Angle Relationships

7.2 Triangles

Classification by Sides

Classification by Angles

Triangle Angle Sum Theorem

The sum of the interior angles of any triangle is always $180^\circ$:

$$\angle A + \angle B + \angle C = 180^\circ$$

Example 1 — Finding a Missing Angle

A triangle has angles $47^\circ$ and $68^\circ$. Find the third angle.

$$\angle C = 180^\circ - 47^\circ - 68^\circ = 65^\circ$$

Since all angles are less than $90^\circ$, this is an acute triangle.

7.3 Perimeter of Polygons

The perimeter is the total distance around the outside of a shape. Add all side lengths.

ShapePerimeter FormulaVariables
Rectangle$P = 2l + 2w$$l$ = length, $w$ = width
Square$P = 4s$$s$ = side length
Triangle$P = a + b + c$$a, b, c$ = three side lengths
Regular $n$-gon$P = ns$$n$ = number of sides, $s$ = side length
Circle (circumference)$C = 2\pi r = \pi d$$r$ = radius, $d$ = diameter

7.4 Area Formulas

Area measures the amount of flat surface enclosed by a shape. Area is always measured in square units (cm², m², ft², etc.).

ShapeArea FormulaNotes
Rectangle$A = lw$length $\times$ width
Square$A = s^2$side squared
Triangle$A = \dfrac{1}{2}bh$$b$ = base, $h$ = perpendicular height
Parallelogram$A = bh$base $\times$ perpendicular height
Trapezoid$A = \dfrac{1}{2}(b_1 + b_2)h$average of two bases $\times$ height
Circle$A = \pi r^2$$r$ = radius; $\pi \approx 3.14159$

Example 2 — Area of a Trapezoid

A trapezoid has parallel bases of $8$ cm and $14$ cm, and a height of $5$ cm. Find its area.

$$A = \frac{1}{2}(b_1 + b_2)h = \frac{1}{2}(8 + 14)(5) = \frac{1}{2}(22)(5) = 55 \text{ cm}^2$$

Example 3 — Area of a Circle

A circular garden has a diameter of $10$ m. Find its area. Use $\pi \approx 3.14$.

Radius: $r = \dfrac{d}{2} = \dfrac{10}{2} = 5$ m
$$A = \pi r^2 \approx 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \text{ m}^2$$

7.5 Surface Area and Volume

Surface area (SA) is the total area of all faces of a 3-D solid, measured in square units. Volume (V) is the amount of space inside a solid, measured in cubic units.

SolidSurface AreaVolume
Rectangular Prism $SA = 2(lw + lh + wh)$ $V = lwh$
Cube $SA = 6s^2$ $V = s^3$
Cylinder $SA = 2\pi r^2 + 2\pi r h$ $V = \pi r^2 h$
Triangular Prism $SA = bh + (a+b+c)H$ $V = \dfrac{1}{2}bh \cdot H$
Cone $SA = \pi r^2 + \pi r l$  ($l$ = slant height) $V = \dfrac{1}{3}\pi r^2 h$
Sphere $SA = 4\pi r^2$ $V = \dfrac{4}{3}\pi r^3$

Example 4 — Volume of a Rectangular Prism

A box is $6$ ft long, $4$ ft wide, and $3$ ft tall. Find its volume and surface area.

$$V = lwh = 6 \times 4 \times 3 = 72 \text{ ft}^3$$ $$SA = 2(lw + lh + wh) = 2(24 + 18 + 12) = 2(54) = 108 \text{ ft}^2$$

Example 5 — Volume of a Cylinder

A cylindrical can has radius $3$ cm and height $10$ cm. Find its volume. Use $\pi \approx 3.14$.

$$V = \pi r^2 h \approx 3.14 \times 9 \times 10 = 282.6 \text{ cm}^3$$

7.6 The Pythagorean Theorem

Pythagorean Theorem

In any right triangle, with legs $a$ and $b$ and hypotenuse $c$ (the side opposite the right angle):

$$a^2 + b^2 = c^2$$

The hypotenuse is always the longest side and is always opposite the right angle ($90^\circ$).

The theorem has two primary uses:

  1. Find the hypotenuse: $c = \sqrt{a^2 + b^2}$
  2. Find a missing leg: $a = \sqrt{c^2 - b^2}$

Example 6 — Finding the Hypotenuse

A right triangle has legs $a = 5$ and $b = 12$. Find the hypotenuse.

$$c = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13$$

The 5-12-13 triple is a common Pythagorean triple.

Example 7 — Real-World Application

A 10-foot ladder leans against a wall. Its base is 6 feet from the wall. How high up the wall does it reach?

Here $c = 10$ (ladder), $b = 6$ (base), and we seek $a$ (height).
$$a = \sqrt{c^2 - b^2} = \sqrt{100 - 36} = \sqrt{64} = 8 \text{ feet}$$

Common Pythagorean Triples to Memorize

These sets of whole numbers satisfy $a^2 + b^2 = c^2$:

Practice Problems

Practice — Chapter 7

  1. Two angles are supplementary. One measures $73^\circ$. Find the other.
  2. A triangle has angles $90^\circ$ and $35^\circ$. Find the third angle and classify the triangle.
  3. Find the perimeter of a rectangle with $l = 9$ m and $w = 5$ m.
  4. Find the area of a triangle with base $14$ cm and height $6$ cm.
  5. A circle has radius $7$ in. Find (a) the circumference and (b) the area. Use $\pi \approx 3.14$.
  6. Find the volume of a rectangular prism with dimensions $5 \times 3 \times 4$ cm.
  7. A cylinder has diameter $8$ ft and height $5$ ft. Find its volume. Use $\pi \approx 3.14$.
  8. A right triangle has legs $9$ and $40$. Find the hypotenuse.
  9. Is a triangle with sides $10$, $24$, $26$ a right triangle? Justify using the Pythagorean theorem.
Show Answers
  1. $180^\circ - 73^\circ = 107^\circ$
  2. $180^\circ - 90^\circ - 35^\circ = 55^\circ$; right triangle (has a $90^\circ$ angle).
  3. $P = 2(9)+2(5) = 28$ m
  4. $A = \frac{1}{2}(14)(6) = 42$ cm$^2$
  5. (a) $C = 2(3.14)(7) = 43.96$ in;   (b) $A = 3.14(49) = 153.86$ in$^2$
  6. $V = 5 \times 3 \times 4 = 60$ cm$^3$
  7. $r = 4$; $V = 3.14(16)(5) = 251.2$ ft$^3$
  8. $c = \sqrt{81+1600} = \sqrt{1681} = 41$
  9. $10^2 + 24^2 = 100 + 576 = 676 = 26^2$ ✓ Yes, it is a right triangle.

Chapter Summary

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